121128433 has 2 divisors, whose sum is σ = 121128434. Its totient is φ = 121128432.

The previous prime is 121128379. The next prime is 121128437. The reversal of 121128433 is 334821121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99440784 + 21687649 = 9972^2 + 4657^2 .

It is an emirp because it is prime and its reverse (334821121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121128433 - 2⁹ = 121127921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121128398 and 121128407.

It is not a weakly prime, because it can be changed into another prime (121128437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60564216 + 60564217.

It is an arithmetic number, because the mean of its divisors is an integer number (60564217).

Almost surely, 2^121128433 is an apocalyptic number.

It is an amenable number.

121128433 is a deficient number, since it is larger than the sum of its proper divisors (1).

121128433 is an equidigital number, since it uses as much as digits as its factorization.

121128433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 25.

The square root of 121128433 is about 11005.8363153374. The cubic root of 121128433 is about 494.7836799245.

Adding to 121128433 its reverse (334821121), we get a palindrome (455949554).

The spelling of 121128433 in words is "one hundred twenty-one million, one hundred twenty-eight thousand, four hundred thirty-three".