Base | Representation |
---|---|
bin | 11011100010101100000011… |
… | …011110110010100010010111 |
3 | 120212220000100010102112011002 |
4 | 123202230003132302202113 |
5 | 111334102312342131210 |
6 | 1105342453423133515 |
7 | 34341266423411540 |
oct | 3342540336624227 |
9 | 525800303375132 |
10 | 121131021052055 |
11 | 35661417560803 |
12 | 11704005a4429b |
13 | 52787b5c98441 |
14 | 21caab640d4c7 |
15 | e00d686be4a5 |
hex | 6e2b037b2897 |
121131021052055 has 32 divisors (see below), whose sum is σ = 169674042249216. Its totient is φ = 81285875720064.
The previous prime is 121131021052033. The next prime is 121131021052147. The reversal of 121131021052055 is 550250120131121.
It is a cyclic number.
It is not a de Polignac number, because 121131021052055 - 26 = 121131021051991 is a prime.
It is a super-2 number, since 2×1211310210520552 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12782297 + ... + 20140733.
It is an arithmetic number, because the mean of its divisors is an integer number (5302313820288).
Almost surely, 2121131021052055 is an apocalyptic number.
121131021052055 is a deficient number, since it is larger than the sum of its proper divisors (48543021197161).
121131021052055 is a wasteful number, since it uses less digits than its factorization.
121131021052055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7368503.
The product of its (nonzero) digits is 3000, while the sum is 29.
Adding to 121131021052055 its reverse (550250120131121), we get a palindrome (671381141183176).
The spelling of 121131021052055 in words is "one hundred twenty-one trillion, one hundred thirty-one billion, twenty-one million, fifty-two thousand, fifty-five".
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