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12113201201 is a prime number
BaseRepresentation
bin10110100100000000…
…01100100000110001
31011021012010101012112
423102000030200301
5144301434414301
65321551535105
7606114340253
oct132200144061
934235111175
1012113201201
11515664a392
12242082a495
1311b074ac9a
1482ca87cd3
154ad6819bb
hex2d200c831

12113201201 has 2 divisors, whose sum is σ = 12113201202. Its totient is φ = 12113201200.

The previous prime is 12113201167. The next prime is 12113201203. The reversal of 12113201201 is 10210231121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10128409600 + 1984791601 = 100640^2 + 44551^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12113201201 is a prime.

Together with 12113201203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12113201203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056600600 + 6056600601.

It is an arithmetic number, because the mean of its divisors is an integer number (6056600601).

Almost surely, 212113201201 is an apocalyptic number.

It is an amenable number.

12113201201 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113201201 is an equidigital number, since it uses as much as digits as its factorization.

12113201201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 12113201201 its reverse (10210231121), we get a palindrome (22323432322).

The spelling of 12113201201 in words is "twelve billion, one hundred thirteen million, two hundred one thousand, two hundred one".