Base | Representation |
---|---|
bin | 1011000001000101001100… |
… | …1011001111110100010111 |
3 | 1120220000021221221010102121 |
4 | 2300101103023033310113 |
5 | 3041430320011411043 |
6 | 41432421224120411 |
7 | 2360102316423565 |
oct | 260212313176427 |
9 | 46800257833377 |
10 | 12113203232023 |
11 | 39501a9485603 |
12 | 1437753306107 |
13 | 69b36871a44a |
14 | 2dc3d438ca35 |
15 | 16015b353ded |
hex | b04532cfd17 |
12113203232023 has 2 divisors, whose sum is σ = 12113203232024. Its totient is φ = 12113203232022.
The previous prime is 12113203231993. The next prime is 12113203232057. The reversal of 12113203232023 is 32023230231121.
12113203232023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12113203232023 - 25 = 12113203231991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12113203232623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056601616011 + 6056601616012.
It is an arithmetic number, because the mean of its divisors is an integer number (6056601616012).
Almost surely, 212113203232023 is an apocalyptic number.
12113203232023 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113203232023 is an equidigital number, since it uses as much as digits as its factorization.
12113203232023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 12113203232023 its reverse (32023230231121), we get a palindrome (44136433463144).
The spelling of 12113203232023 in words is "twelve trillion, one hundred thirteen billion, two hundred three million, two hundred thirty-two thousand, twenty-three".
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