Base | Representation |
---|---|
bin | 10001101000001001000… |
… | …101000100111000011101 |
3 | 11021210122212221101210221 |
4 | 101220021011010320131 |
5 | 124321302233300013 |
6 | 2324251224201341 |
7 | 153341651330026 |
oct | 21501105047035 |
9 | 4253585841727 |
10 | 1211333103133 |
11 | 4277a5a5922a |
12 | 176921009251 |
13 | 8a2c75306aa |
14 | 428b3747c4d |
15 | 21799b2708d |
hex | 11a09144e1d |
1211333103133 has 2 divisors, whose sum is σ = 1211333103134. Its totient is φ = 1211333103132.
The previous prime is 1211333103107. The next prime is 1211333103163. The reversal of 1211333103133 is 3313013331121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1149617128804 + 61715974329 = 1072202^2 + 248427^2 .
It is a cyclic number.
It is not a de Polignac number, because 1211333103133 - 213 = 1211333094941 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1211333103098 and 1211333103107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211333103163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605666551566 + 605666551567.
It is an arithmetic number, because the mean of its divisors is an integer number (605666551567).
Almost surely, 21211333103133 is an apocalyptic number.
It is an amenable number.
1211333103133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211333103133 is an equidigital number, since it uses as much as digits as its factorization.
1211333103133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 1211333103133 its reverse (3313013331121), we get a palindrome (4524346434254).
The spelling of 1211333103133 in words is "one trillion, two hundred eleven billion, three hundred thirty-three million, one hundred three thousand, one hundred thirty-three".
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