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121134132041142 = 23111835365636987
BaseRepresentation
bin11011100010101110111100…
…111010010001010110110110
3120212220022100221022010220010
4123202232330322101112312
5111334130200300304032
61105344130234321050
734341436500365553
oct3342567472212666
9525808327263803
10121134132041142
1135662773638970
1211704733889186
135278b9067029c
1421caccd667a2a
15e00e9b888ccc
hex6e2bbce915b6

121134132041142 has 16 divisors (see below), whose sum is σ = 264292651726272. Its totient is φ = 36707312739720.

The previous prime is 121134132041141. The next prime is 121134132041191. The reversal of 121134132041142 is 241140231431121.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121134132041141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 917682818428 + ... + 917682818559.

It is an arithmetic number, because the mean of its divisors is an integer number (16518290732892).

Almost surely, 2121134132041142 is an apocalyptic number.

121134132041142 is an abundant number, since it is smaller than the sum of its proper divisors (143158519685130).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121134132041142 is a wasteful number, since it uses less digits than its factorization.

121134132041142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1835365637003.

The product of its (nonzero) digits is 4608, while the sum is 30.

Adding to 121134132041142 its reverse (241140231431121), we get a palindrome (362274363472263).

The spelling of 121134132041142 in words is "one hundred twenty-one trillion, one hundred thirty-four billion, one hundred thirty-two million, forty-one thousand, one hundred forty-two".

Divisors: 1 2 3 6 11 22 33 66 1835365636987 3670731273974 5506096910961 11012193821922 20189022006857 40378044013714 60567066020571 121134132041142