12114031333 has 2 divisors, whose sum is σ = 12114031334. Its totient is φ = 12114031332.

The previous prime is 12114031331. The next prime is 12114031439. The reversal of 12114031333 is 33313041121.

12114031333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9160978369 + 2953052964 = 95713^2 + 54342^2 .

It is a cyclic number.

It is not a de Polignac number, because 12114031333 - 2¹ = 12114031331 is a prime.

It is a super-3 number, since 3×12114031333³ (a number of 31 digits) contains 333 as substring.

Together with 12114031331, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12114031331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057015666 + 6057015667.

It is an arithmetic number, because the mean of its divisors is an integer number (6057015667).

Almost surely, 2^12114031333 is an apocalyptic number.

It is an amenable number.

12114031333 is a deficient number, since it is larger than the sum of its proper divisors (1).

12114031333 is an equidigital number, since it uses as much as digits as its factorization.

12114031333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 12114031333 its reverse (33313041121), we get a palindrome (45427072454).

The spelling of 12114031333 in words is "twelve billion, one hundred fourteen million, thirty-one thousand, three hundred thirty-three".