Base | Representation |
---|---|
bin | 111000011010010010… |
… | …0011010001100110100 |
3 | 102120200112020122122002 |
4 | 1300310210122030310 |
5 | 3441044101402040 |
6 | 131352412554432 |
7 | 11515662612233 |
oct | 1606444321464 |
9 | 376615218562 |
10 | 121141044020 |
11 | 47414a63407 |
12 | 1b589a82a18 |
13 | b567708b49 |
14 | 5c12acab1a |
15 | 3240247a15 |
hex | 1c3491a334 |
121141044020 has 24 divisors (see below), whose sum is σ = 263168476200. Its totient is φ = 46785506432.
The previous prime is 121141044019. The next prime is 121141044029. The reversal of 121141044020 is 20440141121.
It can be written as a sum of positive squares in 4 ways, for example, as 33869249296 + 87271794724 = 184036^2 + 295418^2 .
It is a super-3 number, since 3×1211410440203 (a number of 34 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 121141043983 and 121141044001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121141044029) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 104431355 + ... + 104432514.
It is an arithmetic number, because the mean of its divisors is an integer number (10965353175).
Almost surely, 2121141044020 is an apocalyptic number.
121141044020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
121141044020 is an abundant number, since it is smaller than the sum of its proper divisors (142027432180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121141044020 is a wasteful number, since it uses less digits than its factorization.
121141044020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 208863907 (or 208863905 counting only the distinct ones).
The product of its (nonzero) digits is 256, while the sum is 20.
Adding to 121141044020 its reverse (20440141121), we get a palindrome (141581185141).
The spelling of 121141044020 in words is "one hundred twenty-one billion, one hundred forty-one million, forty-four thousand, twenty".
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