Search a number
-
+
1211414302169 is a prime number
BaseRepresentation
bin10001101000001101111…
…010110100110111011001
311021210212112201201221122
4101220031322310313121
5124321434030132134
62324303244415025
7153343655445641
oct21501572646731
94253775651848
101211414302169
11427837879275
12176944247475
138a30b2c0766
14428c0443521
15217a1d1602e
hex11a0deb4dd9

1211414302169 has 2 divisors, whose sum is σ = 1211414302170. Its totient is φ = 1211414302168.

The previous prime is 1211414302073. The next prime is 1211414302171. The reversal of 1211414302169 is 9612034141121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1133245411600 + 78168890569 = 1064540^2 + 279587^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211414302169 - 216 = 1211414236633 is a prime.

It is a super-3 number, since 3×12114143021693 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1211414302171, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1211414302199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605707151084 + 605707151085.

It is an arithmetic number, because the mean of its divisors is an integer number (605707151085).

Almost surely, 21211414302169 is an apocalyptic number.

It is an amenable number.

1211414302169 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211414302169 is an equidigital number, since it uses as much as digits as its factorization.

1211414302169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 35.

The spelling of 1211414302169 in words is "one trillion, two hundred eleven billion, four hundred fourteen million, three hundred two thousand, one hundred sixty-nine".