Base | Representation |
---|---|
bin | 10001101000001101111… |
… | …010110100110111110111 |
3 | 11021210212112201201222202 |
4 | 101220031322310313313 |
5 | 124321434030132244 |
6 | 2324303244415115 |
7 | 153343655446013 |
oct | 21501572646767 |
9 | 4253775651882 |
10 | 1211414302199 |
11 | 4278378792a2 |
12 | 17694424749b |
13 | 8a30b2c078a |
14 | 428c0443543 |
15 | 217a1d1604e |
hex | 11a0deb4df7 |
1211414302199 has 2 divisors, whose sum is σ = 1211414302200. Its totient is φ = 1211414302198.
The previous prime is 1211414302193. The next prime is 1211414302243. The reversal of 1211414302199 is 9912034141121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1211414302199 - 224 = 1211397524983 is a prime.
It is a super-3 number, since 3×12114143021993 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211414302193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605707151099 + 605707151100.
It is an arithmetic number, because the mean of its divisors is an integer number (605707151100).
Almost surely, 21211414302199 is an apocalyptic number.
1211414302199 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211414302199 is an equidigital number, since it uses as much as digits as its factorization.
1211414302199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 38.
The spelling of 1211414302199 in words is "one trillion, two hundred eleven billion, four hundred fourteen million, three hundred two thousand, one hundred ninety-nine".
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