Base | Representation |
---|---|
bin | 10001101000001110100… |
… | …001001000000011001111 |
3 | 11021210220020121211022111 |
4 | 101220032201020003033 |
5 | 124321444112422343 |
6 | 2324304243524451 |
7 | 153344140003144 |
oct | 21501641100317 |
9 | 4253806554274 |
10 | 1211424342223 |
11 | 427842506537 |
12 | 176947689727 |
13 | 8a3103c7614 |
14 | 428c18d83cb |
15 | 217a2b4ac9d |
hex | 11a0e8480cf |
1211424342223 has 2 divisors, whose sum is σ = 1211424342224. Its totient is φ = 1211424342222.
The previous prime is 1211424342221. The next prime is 1211424342229. The reversal of 1211424342223 is 3222434241121.
It is a weak prime.
It is an emirp because it is prime and its reverse (3222434241121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1211424342223 - 21 = 1211424342221 is a prime.
It is a super-3 number, since 3×12114243422233 (a number of 37 digits) contains 333 as substring.
Together with 1211424342221, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211424342221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605712171111 + 605712171112.
It is an arithmetic number, because the mean of its divisors is an integer number (605712171112).
Almost surely, 21211424342223 is an apocalyptic number.
1211424342223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211424342223 is an equidigital number, since it uses as much as digits as its factorization.
1211424342223 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18432, while the sum is 31.
Adding to 1211424342223 its reverse (3222434241121), we get a palindrome (4433858583344).
The spelling of 1211424342223 in words is "one trillion, two hundred eleven billion, four hundred twenty-four million, three hundred forty-two thousand, two hundred twenty-three".
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