Base | Representation |
---|---|
bin | 111000011010010110… |
… | …0101000110101101111 |
3 | 102120200200022020122020 |
4 | 1300310230220311233 |
5 | 3441100124414020 |
6 | 131352531121223 |
7 | 11516020135215 |
oct | 1606454506557 |
9 | 376620266566 |
10 | 121143201135 |
11 | 474161a7050 |
12 | 1b58a743213 |
13 | b567cb2948 |
14 | 5c130cccb5 |
15 | 3240521c40 |
hex | 1c34b28d6f |
121143201135 has 128 divisors (see below), whose sum is σ = 228237419520. Its totient is φ = 54217728000.
The previous prime is 121143201097. The next prime is 121143201139. The reversal of 121143201135 is 531102341121.
It is not a de Polignac number, because 121143201135 - 27 = 121143201007 is a prime.
It is a super-3 number, since 3×1211432011353 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121143201139) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 30878284 + ... + 30882206.
It is an arithmetic number, because the mean of its divisors is an integer number (1783104840).
Almost surely, 2121143201135 is an apocalyptic number.
121143201135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
121143201135 is a deficient number, since it is larger than the sum of its proper divisors (107094218385).
121143201135 is a wasteful number, since it uses less digits than its factorization.
121143201135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4169.
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 121143201135 its reverse (531102341121), we get a palindrome (652245542256).
The spelling of 121143201135 in words is "one hundred twenty-one billion, one hundred forty-three million, two hundred one thousand, one hundred thirty-five".
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