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1211432329997 is a prime number
BaseRepresentation
bin10001101000001110111…
…111100110001100001101
311021210220210122122110222
4101220032333212030031
5124322003134024442
62324305131041125
7153344264622131
oct21501677461415
94253823578428
101211432329997
11427846a718aa
1217694a2a01a5
138a311c63306
14428c29b73c1
15217a36c78d2
hex11a0efe630d

1211432329997 has 2 divisors, whose sum is σ = 1211432329998. Its totient is φ = 1211432329996.

The previous prime is 1211432329931. The next prime is 1211432330131. The reversal of 1211432329997 is 7999232341121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1141619593156 + 69812736841 = 1068466^2 + 264221^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211432329997 - 28 = 1211432329741 is a prime.

It is a super-3 number, since 3×12114323299973 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211432329927) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605716164998 + 605716164999.

It is an arithmetic number, because the mean of its divisors is an integer number (605716164999).

Almost surely, 21211432329997 is an apocalyptic number.

It is an amenable number.

1211432329997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211432329997 is an equidigital number, since it uses as much as digits as its factorization.

1211432329997 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1469664, while the sum is 53.

The spelling of 1211432329997 in words is "one trillion, two hundred eleven billion, four hundred thirty-two million, three hundred twenty-nine thousand, nine hundred ninety-seven".