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12117504013 is a prime number
BaseRepresentation
bin10110100100100001…
…00111000000001101
31011021111012222112221
423102100213000031
5144304040112023
65322224055341
7606166041016
oct132220470015
934244188487
1012117504013
11515901912a
122422164551
1311b15c6624
1482d48800d
154adc3185d
hex2d242700d

12117504013 has 2 divisors, whose sum is σ = 12117504014. Its totient is φ = 12117504012.

The previous prime is 12117503971. The next prime is 12117504031. The reversal of 12117504013 is 31040571121.

Together with next prime (12117504031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6951057129 + 5166446884 = 83373^2 + 71878^2 .

It is a cyclic number.

It is not a de Polignac number, because 12117504013 - 217 = 12117372941 is a prime.

It is a super-2 number, since 2×121175040132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12117504053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6058752006 + 6058752007.

It is an arithmetic number, because the mean of its divisors is an integer number (6058752007).

Almost surely, 212117504013 is an apocalyptic number.

It is an amenable number.

12117504013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12117504013 is an equidigital number, since it uses as much as digits as its factorization.

12117504013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 25.

The spelling of 12117504013 in words is "twelve billion, one hundred seventeen million, five hundred four thousand, thirteen".