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12119985509 is a prime number
BaseRepresentation
bin10110100100110100…
…00100110101100101
31011021122220001112012
423102122010311211
5144310204014014
65322353204005
7606226114502
oct132232046545
934248801465
1012119985509
11515a463555
122422b60605
1311b1c84c78
1482d9324a9
154ae071c3e
hex2d2684d65

12119985509 has 2 divisors, whose sum is σ = 12119985510. Its totient is φ = 12119985508.

The previous prime is 12119985473. The next prime is 12119985511. The reversal of 12119985509 is 90558991121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11130883009 + 989102500 = 105503^2 + 31450^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12119985509 is a prime.

Together with 12119985511, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12119985809) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6059992754 + 6059992755.

It is an arithmetic number, because the mean of its divisors is an integer number (6059992755).

Almost surely, 212119985509 is an apocalyptic number.

It is an amenable number.

12119985509 is a deficient number, since it is larger than the sum of its proper divisors (1).

12119985509 is an equidigital number, since it uses as much as digits as its factorization.

12119985509 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 291600, while the sum is 50.

The spelling of 12119985509 in words is "twelve billion, one hundred nineteen million, nine hundred eighty-five thousand, five hundred nine".