Base | Representation |
---|---|
bin | 10001101000110001100… |
… | …111011100011011000101 |
3 | 11021212102021122221211021 |
4 | 101220301213130123011 |
5 | 124324200334413333 |
6 | 2324442521111141 |
7 | 153364550140642 |
oct | 21506147343305 |
9 | 4255367587737 |
10 | 1212013201093 |
11 | 428014944962 |
12 | 176a909284b1 |
13 | 8a3a53c2116 |
14 | 42939bc0dc9 |
15 | 217d96b782d |
hex | 11a319dc6c5 |
1212013201093 has 2 divisors, whose sum is σ = 1212013201094. Its totient is φ = 1212013201092.
The previous prime is 1212013201073. The next prime is 1212013201121. The reversal of 1212013201093 is 3901023102121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 988002204289 + 224010996804 = 993983^2 + 473298^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1212013201093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1212013201073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606006600546 + 606006600547.
It is an arithmetic number, because the mean of its divisors is an integer number (606006600547).
Almost surely, 21212013201093 is an apocalyptic number.
It is an amenable number.
1212013201093 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212013201093 is an equidigital number, since it uses as much as digits as its factorization.
1212013201093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 1212013201093 in words is "one trillion, two hundred twelve billion, thirteen million, two hundred one thousand, ninety-three".
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