12120204431 has 2 divisors, whose sum is σ = 12120204432. Its totient is φ = 12120204430.

The previous prime is 12120204413. The next prime is 12120204433. The reversal of 12120204431 is 13440202121.

Together with previous prime (12120204413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12120204431 - 2³⁰ = 11046462607 is a prime.

It is a super-2 number, since 2×12120204431² (a number of 21 digits) contains 22 as substring.

Together with 12120204433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12120204433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060102215 + 6060102216.

It is an arithmetic number, because the mean of its divisors is an integer number (6060102216).

Almost surely, 2^12120204431 is an apocalyptic number.

12120204431 is a deficient number, since it is larger than the sum of its proper divisors (1).

12120204431 is an equidigital number, since it uses as much as digits as its factorization.

12120204431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 12120204431 its reverse (13440202121), we get a palindrome (25560406552).

The spelling of 12120204431 in words is "twelve billion, one hundred twenty million, two hundred four thousand, four hundred thirty-one".