Base | Representation |
---|---|
bin | 11011100011101110010000… |
… | …110101100111111011010111 |
3 | 120220010210211120210001022201 |
4 | 123203232100311213323113 |
5 | 111341233411144231403 |
6 | 1105435252011105331 |
7 | 34346364216360244 |
oct | 3343562065477327 |
9 | 526123746701281 |
10 | 121202112102103 |
11 | 3568958860492a |
12 | 11715946142247 |
13 | 528240547bb26 |
14 | 21d02dbcb45cb |
15 | e02b2999921d |
hex | 6e3b90d67ed7 |
121202112102103 has 2 divisors, whose sum is σ = 121202112102104. Its totient is φ = 121202112102102.
The previous prime is 121202112101951. The next prime is 121202112102109. The reversal of 121202112102103 is 301201211202121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121202112102103 - 213 = 121202112093911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121202112102109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60601056051051 + 60601056051052.
It is an arithmetic number, because the mean of its divisors is an integer number (60601056051052).
Almost surely, 2121202112102103 is an apocalyptic number.
121202112102103 is a deficient number, since it is larger than the sum of its proper divisors (1).
121202112102103 is an equidigital number, since it uses as much as digits as its factorization.
121202112102103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 121202112102103 its reverse (301201211202121), we get a palindrome (422403323304224).
The spelling of 121202112102103 in words is "one hundred twenty-one trillion, two hundred two billion, one hundred twelve million, one hundred two thousand, one hundred three".
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