12120313102127 has 2 divisors, whose sum is σ = 12120313102128. Its totient is φ = 12120313102126.

The previous prime is 12120313102091. The next prime is 12120313102129. The reversal of 12120313102127 is 72120131302121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12120313102127 - 2²⁸ = 12120044666671 is a prime.

Together with 12120313102129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12120313102096 and 12120313102105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12120313102129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060156551063 + 6060156551064.

It is an arithmetic number, because the mean of its divisors is an integer number (6060156551064).

Almost surely, 2^{12120313102127} is an apocalyptic number.

12120313102127 is a deficient number, since it is larger than the sum of its proper divisors (1).

12120313102127 is an equidigital number, since it uses as much as digits as its factorization.

12120313102127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 12120313102127 its reverse (72120131302121), we get a palindrome (84240444404248).

The spelling of 12120313102127 in words is "twelve trillion, one hundred twenty billion, three hundred thirteen million, one hundred two thousand, one hundred twenty-seven".