Base | Representation |
---|---|
bin | 11011100011101111001110… |
… | …000110111001110100100110 |
3 | 120220010220111020000210210120 |
4 | 123203233032012321310212 |
5 | 111341243012322321042 |
6 | 1105435542011302410 |
7 | 34346431540616523 |
oct | 3343571606716446 |
9 | 526126436023716 |
10 | 121203140042022 |
11 | 35689a65881355 |
12 | 11715b9244aa06 |
13 | 528253a41c3bc |
14 | 21d039861614a |
15 | e02b89d48dec |
hex | 6e3bce1b9d26 |
121203140042022 has 32 divisors (see below), whose sum is σ = 243810702989280. Its totient is φ = 40166982385920.
The previous prime is 121203140042009. The next prime is 121203140042081. The reversal of 121203140042022 is 220240041302121.
It is a junction number, because it is equal to n+sod(n) for n = 121203140041983 and 121203140042001.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 81850504 + ... + 83318132.
It is an arithmetic number, because the mean of its divisors is an integer number (7619084468415).
Almost surely, 2121203140042022 is an apocalyptic number.
121203140042022 is an abundant number, since it is smaller than the sum of its proper divisors (122607562947258).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121203140042022 is a wasteful number, since it uses less digits than its factorization.
121203140042022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1547368.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 121203140042022 its reverse (220240041302121), we get a palindrome (341443181344143).
The spelling of 121203140042022 in words is "one hundred twenty-one trillion, two hundred three billion, one hundred forty million, forty-two thousand, twenty-two".
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