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1212102013 is a prime number
BaseRepresentation
bin100100000111111…
…0011010101111101
310010110210011101011
41020033303111331
54440244231023
6320135315221
742015461053
oct11017632575
93113704334
101212102013
11572222201
12299b1bb11
13164170a35
14b6da01d3
157162b50d
hex483f357d

1212102013 has 2 divisors, whose sum is σ = 1212102014. Its totient is φ = 1212102012.

The previous prime is 1212101963. The next prime is 1212102019. The reversal of 1212102013 is 3102012121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 967085604 + 245016409 = 31098^2 + 15653^2 .

It is a cyclic number.

It is not a de Polignac number, because 1212102013 - 213 = 1212093821 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1212101984 and 1212102002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1212102019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606051006 + 606051007.

It is an arithmetic number, because the mean of its divisors is an integer number (606051007).

Almost surely, 21212102013 is an apocalyptic number.

It is an amenable number.

1212102013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212102013 is an equidigital number, since it uses as much as digits as its factorization.

1212102013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1212102013 is about 34815.2554636613. The cubic root of 1212102013 is about 1066.2189348237.

Adding to 1212102013 its reverse (3102012121), we get a palindrome (4314114134).

The spelling of 1212102013 in words is "one billion, two hundred twelve million, one hundred two thousand, thirteen".