Base | Representation |
---|---|
bin | 1011000001100010010100… |
… | …0110101100101000011111 |
3 | 1120220202110201222100202021 |
4 | 2300120211012230220133 |
5 | 3042042322134100413 |
6 | 41440153025241011 |
7 | 2360500115641021 |
oct | 260304506545037 |
9 | 46822421870667 |
10 | 12121020221983 |
11 | 395354aa14892 |
12 | 1439175193167 |
13 | 69c0130745aa |
14 | 2dc936618011 |
15 | 16046774e18d |
hex | b06251aca1f |
12121020221983 has 2 divisors, whose sum is σ = 12121020221984. Its totient is φ = 12121020221982.
The previous prime is 12121020221957. The next prime is 12121020222029. The reversal of 12121020221983 is 38912202012121.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12121020221983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12121020221903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060510110991 + 6060510110992.
It is an arithmetic number, because the mean of its divisors is an integer number (6060510110992).
Almost surely, 212121020221983 is an apocalyptic number.
12121020221983 is a deficient number, since it is larger than the sum of its proper divisors (1).
12121020221983 is an equidigital number, since it uses as much as digits as its factorization.
12121020221983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 34.
The spelling of 12121020221983 in words is "twelve trillion, one hundred twenty-one billion, twenty million, two hundred twenty-one thousand, nine hundred eighty-three".
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