Base | Representation |
---|---|
bin | 1011000001100010010100… |
… | …1010000101111100110111 |
3 | 1120220202110210122120210021 |
4 | 2300120211022011330313 |
5 | 3042042322401041434 |
6 | 41440153100310011 |
7 | 2360500126336123 |
oct | 260304512057467 |
9 | 46822423576707 |
10 | 12121021112119 |
11 | 3953550472637 |
12 | 1439175542307 |
13 | 69c0132c67ba |
14 | 2dc9367aa583 |
15 | 160467877cb4 |
hex | b0625285f37 |
12121021112119 has 2 divisors, whose sum is σ = 12121021112120. Its totient is φ = 12121021112118.
The previous prime is 12121021112093. The next prime is 12121021112159. The reversal of 12121021112119 is 91121112012121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12121021112119 - 215 = 12121021079351 is a prime.
It is a super-2 number, since 2×121210211121192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12121021112093 and 12121021112102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12121021112159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060510556059 + 6060510556060.
It is an arithmetic number, because the mean of its divisors is an integer number (6060510556060).
Almost surely, 212121021112119 is an apocalyptic number.
12121021112119 is a deficient number, since it is larger than the sum of its proper divisors (1).
12121021112119 is an equidigital number, since it uses as much as digits as its factorization.
12121021112119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 25.
The spelling of 12121021112119 in words is "twelve trillion, one hundred twenty-one billion, twenty-one million, one hundred twelve thousand, one hundred nineteen".
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