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12121111019981 is a prime number
BaseRepresentation
bin1011000001100010101010…
…0001000100000111001101
31120220202201001211101012002
42300120222201010013031
53042043013410114411
641440210031322045
72360502300466145
oct260305241040715
946822631741162
1012121111019981
1139535971a0757
12143919b680325
1369c028b15812
142dc9446d1925
151604706d733b
hexb062a8441cd

12121111019981 has 2 divisors, whose sum is σ = 12121111019982. Its totient is φ = 12121111019980.

The previous prime is 12121111019957. The next prime is 12121111020017. The reversal of 12121111019981 is 18991011112121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9707841979081 + 2413269040900 = 3115741^2 + 1553470^2 .

It is a cyclic number.

It is not a de Polignac number, because 12121111019981 - 222 = 12121106825677 is a prime.

It is a super-2 number, since 2×121211110199812 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12121111019581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060555509990 + 6060555509991.

It is an arithmetic number, because the mean of its divisors is an integer number (6060555509991).

Almost surely, 212121111019981 is an apocalyptic number.

It is an amenable number.

12121111019981 is a deficient number, since it is larger than the sum of its proper divisors (1).

12121111019981 is an equidigital number, since it uses as much as digits as its factorization.

12121111019981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 38.

The spelling of 12121111019981 in words is "twelve trillion, one hundred twenty-one billion, one hundred eleven million, nineteen thousand, nine hundred eighty-one".