Base | Representation |
---|---|
bin | 1011000001100010101100… |
… | …0111100011100010111111 |
3 | 1120220202201202211000101011 |
4 | 2300120223013203202333 |
5 | 3042043024001011312 |
6 | 41440211031500051 |
7 | 2360502452322544 |
oct | 260305307434277 |
9 | 46822652730334 |
10 | 12121121110207 |
11 | 39535a196268a |
12 | 14391a2b27627 |
13 | 69c02ac39475 |
14 | 2dc945b9abcb |
15 | 16047152bda7 |
hex | b062b1e38bf |
12121121110207 has 2 divisors, whose sum is σ = 12121121110208. Its totient is φ = 12121121110206.
The previous prime is 12121121110199. The next prime is 12121121110213. The reversal of 12121121110207 is 70201112112121.
It is a strong prime.
It is an emirp because it is prime and its reverse (70201112112121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12121121110207 - 23 = 12121121110199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12121121110237) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060560555103 + 6060560555104.
It is an arithmetic number, because the mean of its divisors is an integer number (6060560555104).
Almost surely, 212121121110207 is an apocalyptic number.
12121121110207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12121121110207 is an equidigital number, since it uses as much as digits as its factorization.
12121121110207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 12121121110207 its reverse (70201112112121), we get a palindrome (82322233222328).
The spelling of 12121121110207 in words is "twelve trillion, one hundred twenty-one billion, one hundred twenty-one million, one hundred ten thousand, two hundred seven".
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