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12121423333 is a prime number
BaseRepresentation
bin10110100100111111…
…00011110111100101
31011021202121002211221
423102133203313211
5144311041021313
65322444100341
7606244253425
oct132237436745
934252532757
1012121423333
115160255838
1224235346b1
1311b2369556
1482dbc8485
154ae257c8d
hex2d27e3de5

12121423333 has 2 divisors, whose sum is σ = 12121423334. Its totient is φ = 12121423332.

The previous prime is 12121423313. The next prime is 12121423339. The reversal of 12121423333 is 33332412121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11581418689 + 540004644 = 107617^2 + 23238^2 .

It is an emirp because it is prime and its reverse (33332412121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12121423333 - 221 = 12119326181 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12121423298 and 12121423307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12121423339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060711666 + 6060711667.

It is an arithmetic number, because the mean of its divisors is an integer number (6060711667).

Almost surely, 212121423333 is an apocalyptic number.

It is an amenable number.

12121423333 is a deficient number, since it is larger than the sum of its proper divisors (1).

12121423333 is an equidigital number, since it uses as much as digits as its factorization.

12121423333 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 25.

Adding to 12121423333 its reverse (33332412121), we get a palindrome (45453835454).

The spelling of 12121423333 in words is "twelve billion, one hundred twenty-one million, four hundred twenty-three thousand, three hundred thirty-three".