Base | Representation |
---|---|
bin | 1011000001100110000000… |
… | …0110011001101011100111 |
3 | 1120220212000201102022002011 |
4 | 2300121200012121223213 |
5 | 3042101334030000403 |
6 | 41440435143455051 |
7 | 2360533464626353 |
oct | 260314006315347 |
9 | 46825021368064 |
10 | 12122010000103 |
11 | 3953a08696833 |
12 | 14393b0757487 |
13 | 69c140142c13 |
14 | 2dc9cbc64463 |
15 | 1604c45b1a6d |
hex | b0660199ae7 |
12122010000103 has 2 divisors, whose sum is σ = 12122010000104. Its totient is φ = 12122010000102.
The previous prime is 12122010000083. The next prime is 12122010000169. The reversal of 12122010000103 is 30100001022121.
It is a weak prime.
It is an emirp because it is prime and its reverse (30100001022121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12122010000103 - 29 = 12122009999591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12122010000703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061005000051 + 6061005000052.
It is an arithmetic number, because the mean of its divisors is an integer number (6061005000052).
Almost surely, 212122010000103 is an apocalyptic number.
12122010000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122010000103 is an equidigital number, since it uses as much as digits as its factorization.
12122010000103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 12122010000103 its reverse (30100001022121), we get a palindrome (42222011022224).
The spelling of 12122010000103 in words is "twelve trillion, one hundred twenty-two billion, ten million, one hundred three", and thus it is an aban number.
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