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121220111155471 is a prime number
BaseRepresentation
bin11011100011111111000001…
…101010100100000100001111
3120220012112021222011200210221
4123203333001222210010033
5111342032241423433341
61105451430021212211
734350602233660426
oct3343770152440417
9526175258150727
10121220111155471
1135696184600049
1211719329b61067
13528401343a573
1421d11285362bd
15e0332ec16ed1
hex6e3fc1aa410f

121220111155471 has 2 divisors, whose sum is σ = 121220111155472. Its totient is φ = 121220111155470.

The previous prime is 121220111155427. The next prime is 121220111155547. The reversal of 121220111155471 is 174551111022121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 121220111155471 - 211 = 121220111153423 is a prime.

It is a super-3 number, since 3×1212201111554713 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121220111155411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60610055577735 + 60610055577736.

It is an arithmetic number, because the mean of its divisors is an integer number (60610055577736).

Almost surely, 2121220111155471 is an apocalyptic number.

121220111155471 is a deficient number, since it is larger than the sum of its proper divisors (1).

121220111155471 is an equidigital number, since it uses as much as digits as its factorization.

121220111155471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5600, while the sum is 34.

Adding to 121220111155471 its reverse (174551111022121), we get a palindrome (295771222177592).

The spelling of 121220111155471 in words is "one hundred twenty-one trillion, two hundred twenty billion, one hundred eleven million, one hundred fifty-five thousand, four hundred seventy-one".