Base | Representation |
---|---|
bin | 10001101000111100111… |
… | …000000100110001000110 |
3 | 11021212220110010112011021 |
4 | 101220330320010301012 |
5 | 124330042220010042 |
6 | 2324513350101354 |
7 | 153402332632561 |
oct | 21507470046106 |
9 | 4255813115137 |
10 | 1212202110022 |
11 | 428101541a42 |
12 | 176b2404a85a |
13 | 8a405595057 |
14 | 42956d174d8 |
15 | 217eb080867 |
hex | 11a3ce04c46 |
1212202110022 has 4 divisors (see below), whose sum is σ = 1818303165036. Its totient is φ = 606101055010.
The previous prime is 1212202109827. The next prime is 1212202110029. The reversal of 1212202110022 is 2200112022121.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 1212202109978 and 1212202110005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1212202110029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 303050527504 + ... + 303050527507.
It is an arithmetic number, because the mean of its divisors is an integer number (454575791259).
Almost surely, 21212202110022 is an apocalyptic number.
1212202110022 is a deficient number, since it is larger than the sum of its proper divisors (606101055014).
1212202110022 is an equidigital number, since it uses as much as digits as its factorization.
1212202110022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 606101055013.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 1212202110022 its reverse (2200112022121), we get a palindrome (3412314132143).
The spelling of 1212202110022 in words is "one trillion, two hundred twelve billion, two hundred two million, one hundred ten thousand, twenty-two".
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