Base | Representation |
---|---|
bin | 1011000001100110011011… |
… | …0001101110010010101011 |
3 | 1120220212022112012111111122 |
4 | 2300121212301232102223 |
5 | 3042102101214120021 |
6 | 41440454224445455 |
7 | 2360536325033123 |
oct | 260314661562253 |
9 | 46825275174448 |
10 | 12122122020011 |
11 | 3953a65947a73 |
12 | 143942217988b |
13 | 69c15a4047a3 |
14 | 2dc9dcaa3c83 |
15 | 1604ce33cbab |
hex | b0666c6e4ab |
12122122020011 has 2 divisors, whose sum is σ = 12122122020012. Its totient is φ = 12122122020010.
The previous prime is 12122122019981. The next prime is 12122122020013. The reversal of 12122122020011 is 11002022122121.
12122122020011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12122122020011 - 210 = 12122122018987 is a prime.
Together with 12122122020013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12122122020013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061061010005 + 6061061010006.
It is an arithmetic number, because the mean of its divisors is an integer number (6061061010006).
Almost surely, 212122122020011 is an apocalyptic number.
12122122020011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122122020011 is an equidigital number, since it uses as much as digits as its factorization.
12122122020011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 12122122020011 its reverse (11002022122121), we get a palindrome (23124144142132).
The spelling of 12122122020011 in words is "twelve trillion, one hundred twenty-two billion, one hundred twenty-two million, twenty thousand, eleven".
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