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121222121220257 is a prime number
BaseRepresentation
bin11011100100000000111001…
…011110010110100010100001
3120220012201111001110120022212
4123210000321132112202201
5111342100401013022012
61105452401304011505
734351003112151551
oct3344007136264241
9526181431416285
10121222121220257
11356970161a1512
12117197ab160b95
1352842739c9b05
1421d1279491161
15e033eb416b22
hex6e40397968a1

121222121220257 has 2 divisors, whose sum is σ = 121222121220258. Its totient is φ = 121222121220256.

The previous prime is 121222121220169. The next prime is 121222121220259. The reversal of 121222121220257 is 752022121222121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118533715007761 + 2688406212496 = 10887319^2 + 1639636^2 .

It is a cyclic number.

It is not a de Polignac number, because 121222121220257 - 214 = 121222121203873 is a prime.

Together with 121222121220259, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (121222121220259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60611060610128 + 60611060610129.

It is an arithmetic number, because the mean of its divisors is an integer number (60611060610129).

Almost surely, 2121222121220257 is an apocalyptic number.

It is an amenable number.

121222121220257 is a deficient number, since it is larger than the sum of its proper divisors (1).

121222121220257 is an equidigital number, since it uses as much as digits as its factorization.

121222121220257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8960, while the sum is 32.

Adding to 121222121220257 its reverse (752022121222121), we get a palindrome (873244242442378).

The spelling of 121222121220257 in words is "one hundred twenty-one trillion, two hundred twenty-two billion, one hundred twenty-one million, two hundred twenty thousand, two hundred fifty-seven".