Base | Representation |
---|---|
bin | 1011000001100111000110… |
… | …0100001110100001101011 |
3 | 1120220212210010210211110021 |
4 | 2300121301210032201223 |
5 | 3042102434034001103 |
6 | 41440524212301311 |
7 | 2360543653433125 |
oct | 260316144164153 |
9 | 46825703724407 |
10 | 12122303031403 |
11 | 3954049040564 |
12 | 1439472911837 |
13 | 69c188a70b16 |
14 | 2dca18b42215 |
15 | 1604e0195bbd |
hex | b067190e86b |
12122303031403 has 2 divisors, whose sum is σ = 12122303031404. Its totient is φ = 12122303031402.
The previous prime is 12122303031367. The next prime is 12122303031439. The reversal of 12122303031403 is 30413030322121.
It is a balanced prime because it is at equal distance from previous prime (12122303031367) and next prime (12122303031439).
It is an emirp because it is prime and its reverse (30413030322121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12122303031403 - 233 = 12113713096811 is a prime.
It is not a weakly prime, because it can be changed into another prime (12122303041403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061151515701 + 6061151515702.
It is an arithmetic number, because the mean of its divisors is an integer number (6061151515702).
Almost surely, 212122303031403 is an apocalyptic number.
12122303031403 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122303031403 is an equidigital number, since it uses as much as digits as its factorization.
12122303031403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 12122303031403 its reverse (30413030322121), we get a palindrome (42535333353524).
The spelling of 12122303031403 in words is "twelve trillion, one hundred twenty-two billion, three hundred three million, thirty-one thousand, four hundred three".
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