Base | Representation |
---|---|
bin | 10110100101001011… |
… | …00101000100110101 |
3 | 1011021212120021012021 |
4 | 23102211211010311 |
5 | 144311442014031 |
6 | 5322541553141 |
7 | 606263544436 |
oct | 132245450465 |
9 | 34255507167 |
10 | 12123001141 |
11 | 5161133209 |
12 | 2423b757b1 |
13 | 11b279c774 |
14 | 8300b948d |
15 | 4ae46a511 |
hex | 2d2965135 |
12123001141 has 2 divisors, whose sum is σ = 12123001142. Its totient is φ = 12123001140.
The previous prime is 12123001139. The next prime is 12123001151. The reversal of 12123001141 is 14110032121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9229637041 + 2893364100 = 96071^2 + 53790^2 .
It is a cyclic number.
It is not a de Polignac number, because 12123001141 - 21 = 12123001139 is a prime.
It is a super-3 number, since 3×121230011413 (a number of 31 digits) contains 333 as substring.
Together with 12123001139, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12123001151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061500570 + 6061500571.
It is an arithmetic number, because the mean of its divisors is an integer number (6061500571).
Almost surely, 212123001141 is an apocalyptic number.
It is an amenable number.
12123001141 is a deficient number, since it is larger than the sum of its proper divisors (1).
12123001141 is an equidigital number, since it uses as much as digits as its factorization.
12123001141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 12123001141 its reverse (14110032121), we get a palindrome (26233033262).
The spelling of 12123001141 in words is "twelve billion, one hundred twenty-three million, one thousand, one hundred forty-one".
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