121243134114077 has 2 divisors, whose sum is σ = 121243134114078. Its totient is φ = 121243134114076.

The previous prime is 121243134114043. The next prime is 121243134114079. The reversal of 121243134114077 is 770411431342121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94313407057081 + 26929727056996 = 9711509^2 + 5189386^2 .

It is a cyclic number.

It is not a de Polignac number, because 121243134114077 - 2¹⁶ = 121243134048541 is a prime.

Together with 121243134114079, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121243134114079) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60621567057038 + 60621567057039.

It is an arithmetic number, because the mean of its divisors is an integer number (60621567057039).

Almost surely, 2^{121243134114077} is an apocalyptic number.

It is an amenable number.

121243134114077 is a deficient number, since it is larger than the sum of its proper divisors (1).

121243134114077 is an equidigital number, since it uses as much as digits as its factorization.

121243134114077 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112896, while the sum is 41.

Adding to 121243134114077 its reverse (770411431342121), we get a palindrome (891654565456198).

The spelling of 121243134114077 in words is "one hundred twenty-one trillion, two hundred forty-three billion, one hundred thirty-four million, one hundred fourteen thousand, seventy-seven".