Search a number
-
+
12130014203120 = 2451113784107049
BaseRepresentation
bin1011000010000011110100…
…1100000000110011110000
31120221121200112201221102202
42300200331030000303300
53042214232113444440
641444241313402332
72361236026343252
oct260407514006360
946847615657382
1012130014203120
113957345874a50
12143aa652693a8
1369cb174c8118
142dd14ad03cd2
151607e213c615
hexb083d300cf0

12130014203120 has 40 divisors (see below), whose sum is σ = 30766126935600. Its totient is φ = 4410914255360.

The previous prime is 12130014203117. The next prime is 12130014203129. The reversal of 12130014203120 is 2130241003121.

It is a tau number, because it is divible by the number of its divisors (40).

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 12130014203092 and 12130014203101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12130014203129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6892052645 + ... + 6892054404.

It is an arithmetic number, because the mean of its divisors is an integer number (769153173390).

Almost surely, 212130014203120 is an apocalyptic number.

12130014203120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12130014203120 is an abundant number, since it is smaller than the sum of its proper divisors (18636112732480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12130014203120 is a wasteful number, since it uses less digits than its factorization.

12130014203120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13784107073 (or 13784107067 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 12130014203120 its reverse (2130241003121), we get a palindrome (14260255206241).

The spelling of 12130014203120 in words is "twelve trillion, one hundred thirty billion, fourteen million, two hundred three thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 11 16 20 22 40 44 55 80 88 110 176 220 440 880 13784107049 27568214098 55136428196 68920535245 110272856392 137841070490 151625177539 220545712784 275682140980 303250355078 551364281960 606500710156 758125887695 1102728563920 1213001420312 1516251775390 2426002840624 3032503550780 6065007101560 12130014203120