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12130220110039 is a prime number
BaseRepresentation
bin1011000010000100100101…
…1101011111000011010111
31120221122012220012002121221
42300201021131133003113
53042220142322010124
641444313550551211
72361244106462053
oct260411135370327
946848186162557
1012130220110039
113957441021959
12143ab02208507
1369cb4b06cc35
142dd16a3c2c63
15160805261ce4
hexb084975f0d7

12130220110039 has 2 divisors, whose sum is σ = 12130220110040. Its totient is φ = 12130220110038.

The previous prime is 12130220110013. The next prime is 12130220110093. The reversal of 12130220110039 is 93001102203121.

12130220110039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (12130220110093) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12130220110039 - 231 = 12128072626391 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12130220109995 and 12130220110022.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12130220110139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065110055019 + 6065110055020.

It is an arithmetic number, because the mean of its divisors is an integer number (6065110055020).

Almost surely, 212130220110039 is an apocalyptic number.

12130220110039 is a deficient number, since it is larger than the sum of its proper divisors (1).

12130220110039 is an equidigital number, since it uses as much as digits as its factorization.

12130220110039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 12130220110039 in words is "twelve trillion, one hundred thirty billion, two hundred twenty million, one hundred ten thousand, thirty-nine".