Base | Representation |
---|---|
bin | 11011100101010010101100… |
… | …110001101011101000101111 |
3 | 120220112010012100020112221222 |
4 | 123211102230301223220233 |
5 | 111400020241440410132 |
6 | 1110001005103013555 |
7 | 34360232526112544 |
oct | 3345225461535057 |
9 | 526463170215858 |
10 | 121309955013167 |
11 | 35720299074108 |
12 | 1173282259a2bb |
13 | 528c630abcc3b |
14 | 21d560c7cabcb |
15 | e0583c4ee412 |
hex | 6e54acc6ba2f |
121309955013167 has 2 divisors, whose sum is σ = 121309955013168. Its totient is φ = 121309955013166.
The previous prime is 121309955013097. The next prime is 121309955013217. The reversal of 121309955013167 is 761310559903121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121309955013167 - 216 = 121309954947631 is a prime.
It is a super-2 number, since 2×1213099550131672 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121309955093167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60654977506583 + 60654977506584.
It is an arithmetic number, because the mean of its divisors is an integer number (60654977506584).
Almost surely, 2121309955013167 is an apocalyptic number.
121309955013167 is a deficient number, since it is larger than the sum of its proper divisors (1).
121309955013167 is an equidigital number, since it uses as much as digits as its factorization.
121309955013167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1530900, while the sum is 53.
The spelling of 121309955013167 in words is "one hundred twenty-one trillion, three hundred nine billion, nine hundred fifty-five million, thirteen thousand, one hundred sixty-seven".
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