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1213100111141 is a prime number
BaseRepresentation
bin10001101001110010011…
…001101011010100100101
311021222020000212201002222
4101221302121223110211
5124333412112024031
62325142425242125
7153433515544622
oct21516231532445
94258200781088
101213100111141
11428522429526
12177134933345
138a51963b969
1442a002b3349
152184ed14e7b
hex11a7266b525

1213100111141 has 2 divisors, whose sum is σ = 1213100111142. Its totient is φ = 1213100111140.

The previous prime is 1213100111137. The next prime is 1213100111177. The reversal of 1213100111141 is 1411110013121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1109767437025 + 103332674116 = 1053455^2 + 321454^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213100111141 - 22 = 1213100111137 is a prime.

It is a super-2 number, since 2×12131001111412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213100111191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606550055570 + 606550055571.

It is an arithmetic number, because the mean of its divisors is an integer number (606550055571).

Almost surely, 21213100111141 is an apocalyptic number.

It is an amenable number.

1213100111141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213100111141 is an equidigital number, since it uses as much as digits as its factorization.

1213100111141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 1213100111141 its reverse (1411110013121), we get a palindrome (2624210124262).

The spelling of 1213100111141 in words is "one trillion, two hundred thirteen billion, one hundred million, one hundred eleven thousand, one hundred forty-one".