Base | Representation |
---|---|
bin | 10001101001110010100… |
… | …000111000101101110011 |
3 | 11021222020011102201112011 |
4 | 101221302200320231303 |
5 | 124333413103013021 |
6 | 2325142533543351 |
7 | 153433540605505 |
oct | 21516240705563 |
9 | 4258204381464 |
10 | 1213102001011 |
11 | 4285234aa3aa |
12 | 1771354a4b57 |
13 | 8a519b50c24 |
14 | 42a00645d75 |
15 | 21850089de1 |
hex | 11a72838b73 |
1213102001011 has 2 divisors, whose sum is σ = 1213102001012. Its totient is φ = 1213102001010.
The previous prime is 1213102001009. The next prime is 1213102001017. The reversal of 1213102001011 is 1101002013121.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (1101002013121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1213102001011 - 21 = 1213102001009 is a prime.
Together with 1213102001009, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1213102000982 and 1213102001000.
It is not a weakly prime, because it can be changed into another prime (1213102001017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606551000505 + 606551000506.
It is an arithmetic number, because the mean of its divisors is an integer number (606551000506).
Almost surely, 21213102001011 is an apocalyptic number.
1213102001011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213102001011 is an equidigital number, since it uses as much as digits as its factorization.
1213102001011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 1213102001011 its reverse (1101002013121), we get a palindrome (2314104014132).
The spelling of 1213102001011 in words is "one trillion, two hundred thirteen billion, one hundred two million, one thousand, eleven".
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