Base | Representation |
---|---|
bin | 10001101001110011000… |
… | …111011010110011011111 |
3 | 11021222020212102220121222 |
4 | 101221303013122303133 |
5 | 124333423144231421 |
6 | 2325143534243555 |
7 | 153434022506000 |
oct | 21516307326337 |
9 | 4258225386558 |
10 | 1213112102111 |
11 | 428529179518 |
12 | 1771389565bb |
13 | 8a51bc79800 |
14 | 42a01b151a7 |
15 | 21850dd2cab |
hex | 11a731dacdf |
1213112102111 has 48 divisors (see below), whose sum is σ = 1560810513600. Its totient is φ = 941712670080.
The previous prime is 1213112102099. The next prime is 1213112102117. The reversal of 1213112102111 is 1112012113121.
It is a de Polignac number, because none of the positive numbers 2k-1213112102111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1213112102111.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1213112102117) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2874821 + ... + 3269681.
It is an arithmetic number, because the mean of its divisors is an integer number (32516885700).
Almost surely, 21213112102111 is an apocalyptic number.
1213112102111 is a deficient number, since it is larger than the sum of its proper divisors (347698411489).
1213112102111 is an equidigital number, since it uses as much as digits as its factorization.
1213112102111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 394961 (or 394934 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 1213112102111 its reverse (1112012113121), we get a palindrome (2325124215232).
The spelling of 1213112102111 in words is "one trillion, two hundred thirteen billion, one hundred twelve million, one hundred two thousand, one hundred eleven".
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