Base | Representation |
---|---|
bin | 10110100110001001… |
… | …11001101101100010 |
3 | 1011022110000102112222 |
4 | 23103010321231202 |
5 | 144321042242010 |
6 | 5323433551042 |
7 | 606423413252 |
oct | 132304715542 |
9 | 34273012488 |
10 | 12131212130 |
11 | 5165831254 |
12 | 2426875482 |
13 | 11b43b5c3b |
14 | 831215962 |
15 | 4b003d355 |
hex | 2d3139b62 |
12131212130 has 32 divisors (see below), whose sum is σ = 22210632000. Its totient is φ = 4769392320.
The previous prime is 12131212127. The next prime is 12131212141. The reversal of 12131212130 is 3121213121.
12131212130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 12131212099 and 12131212108.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 907757 + ... + 921023.
It is an arithmetic number, because the mean of its divisors is an integer number (694082250).
Almost surely, 212131212130 is an apocalyptic number.
12131212130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12131212130 is a deficient number, since it is larger than the sum of its proper divisors (10079419870).
12131212130 is a wasteful number, since it uses less digits than its factorization.
12131212130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14834.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 12131212130 its reverse (3121213121), we get a palindrome (15252425251).
Subtracting from 12131212130 its reverse (3121213121), we obtain a palindrome (9009999009).
The spelling of 12131212130 in words is "twelve billion, one hundred thirty-one million, two hundred twelve thousand, one hundred thirty".
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