Base | Representation |
---|---|
bin | 10001101001110100001… |
… | …100001010100010100111 |
3 | 11021222022010100111020021 |
4 | 101221310030022202213 |
5 | 124333442302422211 |
6 | 2325145420420011 |
7 | 153434331624202 |
oct | 21516414124247 |
9 | 4258263314207 |
10 | 1213130123431 |
11 | 428538368176 |
12 | 1771429a7607 |
13 | 8a522919405 |
14 | 42a04286939 |
15 | 21852792771 |
hex | 11a7430a8a7 |
1213130123431 has 2 divisors, whose sum is σ = 1213130123432. Its totient is φ = 1213130123430.
The previous prime is 1213130123419. The next prime is 1213130123501. The reversal of 1213130123431 is 1343210313121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1213130123431 - 223 = 1213121734823 is a prime.
It is a super-2 number, since 2×12131301234312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1213130123396 and 1213130123405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1213130123411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606565061715 + 606565061716.
It is an arithmetic number, because the mean of its divisors is an integer number (606565061716).
Almost surely, 21213130123431 is an apocalyptic number.
1213130123431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213130123431 is an equidigital number, since it uses as much as digits as its factorization.
1213130123431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1213130123431 its reverse (1343210313121), we get a palindrome (2556340436552).
The spelling of 1213130123431 in words is "one trillion, two hundred thirteen billion, one hundred thirty million, one hundred twenty-three thousand, four hundred thirty-one".
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