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121313220114809 is a prime number
BaseRepresentation
bin11011100101010101101111…
…011001000011100101111001
3120220112102121220002220101102
4123211111233121003211321
5111400043433322133214
61110002305101301145
734360406454035402
oct3345255731034571
9526472556086342
10121313220114809
1135721714142318
1211733393b647b5
13528ca313a3848
1421d583c2c09a9
15e0597deabbde
hex6e556f643979

121313220114809 has 2 divisors, whose sum is σ = 121313220114810. Its totient is φ = 121313220114808.

The previous prime is 121313220114773. The next prime is 121313220114811. The reversal of 121313220114809 is 908411022313121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69743543587600 + 51569676527209 = 8351260^2 + 7181203^2 .

It is a cyclic number.

It is not a de Polignac number, because 121313220114809 - 212 = 121313220110713 is a prime.

It is a super-2 number, since 2×1213132201148092 (a number of 29 digits) contains 22 as substring.

Together with 121313220114811, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (121313220114829) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60656610057404 + 60656610057405.

It is an arithmetic number, because the mean of its divisors is an integer number (60656610057405).

Almost surely, 2121313220114809 is an apocalyptic number.

It is an amenable number.

121313220114809 is a deficient number, since it is larger than the sum of its proper divisors (1).

121313220114809 is an equidigital number, since it uses as much as digits as its factorization.

121313220114809 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 38.

The spelling of 121313220114809 in words is "one hundred twenty-one trillion, three hundred thirteen billion, two hundred twenty million, one hundred fourteen thousand, eight hundred nine".