12131401743541 has 2 divisors, whose sum is σ = 12131401743542. Its totient is φ = 12131401743540.

The previous prime is 12131401743493. The next prime is 12131401743589. The reversal of 12131401743541 is 14534710413121.

12131401743541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (12131401743493) and next prime (12131401743589).

It can be written as a sum of positive squares in only one way, i.e., 7202535532516 + 4928866211025 = 2683754^2 + 2220105^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12131401743541 is a prime.

It is a super-2 number, since 2×12131401743541² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12131401743541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12131401741541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065700871770 + 6065700871771.

It is an arithmetic number, because the mean of its divisors is an integer number (6065700871771).

Almost surely, 2^{12131401743541} is an apocalyptic number.

It is an amenable number.

12131401743541 is a deficient number, since it is larger than the sum of its proper divisors (1).

12131401743541 is an equidigital number, since it uses as much as digits as its factorization.

12131401743541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 37.

The spelling of 12131401743541 in words is "twelve trillion, one hundred thirty-one billion, four hundred one million, seven hundred forty-three thousand, five hundred forty-one".