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1213202023120 = 24515165025289
BaseRepresentation
bin10001101001111000011…
…110011100001011010000
311021222111010122101001201
4101221320132130023100
5124334114204214440
62325200505440544
7153436164022243
oct21517036341320
94258433571051
101213202023120
11428574a064aa
12177162aa0154
138a5347a17c9
1442a0da4125a
1521858c4619a
hex11a7879c2d0

1213202023120 has 20 divisors (see below), whose sum is σ = 2820694703940. Its totient is φ = 485280809216.

The previous prime is 1213202023063. The next prime is 1213202023129. The reversal of 1213202023120 is 213202023121.

It can be written as a sum of positive squares in 2 ways, for example, as 929010677904 + 284191345216 = 963852^2 + 533096^2 .

It is a tau number, because it is divible by the number of its divisors (20).

It is a super-2 number, since 2×12132020231202 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213202023129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7582512565 + ... + 7582512724.

It is an arithmetic number, because the mean of its divisors is an integer number (141034735197).

Almost surely, 21213202023120 is an apocalyptic number.

1213202023120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1213202023120 is an abundant number, since it is smaller than the sum of its proper divisors (1607492680820).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1213202023120 is a wasteful number, since it uses less digits than its factorization.

1213202023120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15165025302 (or 15165025296 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 1213202023120 its reverse (213202023121), we get a palindrome (1426404046241).

Subtracting from 1213202023120 its reverse (213202023121), we obtain a palindrome (999999999999).

The spelling of 1213202023120 in words is "one trillion, two hundred thirteen billion, two hundred two million, twenty-three thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 40 80 15165025289 30330050578 60660101156 75825126445 121320202312 151650252890 242640404624 303300505780 606601011560 1213202023120