Base | Representation |
---|---|
bin | 11011100101011101000001… |
… | …000001000111100101110111 |
3 | 120220120011210022120220222212 |
4 | 123211131001001013211313 |
5 | 111400210433144204031 |
6 | 1110010040201444035 |
7 | 34361104162124225 |
oct | 3345350101074567 |
9 | 526504708526885 |
10 | 121321032022391 |
11 | 35724a62820093 |
12 | 117349b41a061b |
13 | 52906a796b576 |
14 | 21d5d7d9c5b15 |
15 | e05c89c0112b |
hex | 6e5741047977 |
121321032022391 has 2 divisors, whose sum is σ = 121321032022392. Its totient is φ = 121321032022390.
The previous prime is 121321032022319. The next prime is 121321032022441. The reversal of 121321032022391 is 193220230123121.
Together with previous prime (121321032022319) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121321032022391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121321032022691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60660516011195 + 60660516011196.
It is an arithmetic number, because the mean of its divisors is an integer number (60660516011196).
Almost surely, 2121321032022391 is an apocalyptic number.
121321032022391 is a deficient number, since it is larger than the sum of its proper divisors (1).
121321032022391 is an equidigital number, since it uses as much as digits as its factorization.
121321032022391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 32.
The spelling of 121321032022391 in words is "one hundred twenty-one trillion, three hundred twenty-one billion, thirty-two million, twenty-two thousand, three hundred ninety-one".
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