1213214111 has 2 divisors, whose sum is σ = 1213214112. Its totient is φ = 1213214110.

The previous prime is 1213214099. The next prime is 1213214113. The reversal of 1213214111 is 1114123121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1213214111 is a prime.

It is a Sophie Germain prime.

Together with 1213214113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1213214111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213214113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606607055 + 606607056.

It is an arithmetic number, because the mean of its divisors is an integer number (606607056).

Almost surely, 2^1213214111 is an apocalyptic number.

1213214111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213214111 is an equidigital number, since it uses as much as digits as its factorization.

1213214111 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48, while the sum is 17.

The square root of 1213214111 is about 34831.2232199789. The cubic root of 1213214111 is about 1066.5449187975.

Adding to 1213214111 its reverse (1114123121), we get a palindrome (2327337232).

The spelling of 1213214111 in words is "one billion, two hundred thirteen million, two hundred fourteen thousand, one hundred eleven".