Base | Representation |
---|---|
bin | 10110100110010000… |
… | …11100101111000110 |
3 | 1011022111202200010102 |
4 | 23103020130233012 |
5 | 144321312021042 |
6 | 5323505524102 |
7 | 606434335310 |
oct | 132310345706 |
9 | 34274680112 |
10 | 12132142022 |
11 | 5166306960 |
12 | 2427043632 |
13 | 11b4650280 |
14 | 8313b87b0 |
15 | 4b0173b32 |
hex | 2d321cbc6 |
12132142022 has 96 divisors (see below), whose sum is σ = 24772656384. Its totient is φ = 4303540800.
The previous prime is 12132142003. The next prime is 12132142027. The reversal of 12132142022 is 22024123121.
12132142022 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 12132141985 and 12132142003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12132142027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 12493997 + ... + 12494967.
It is an arithmetic number, because the mean of its divisors is an integer number (258048504).
Almost surely, 212132142022 is an apocalyptic number.
12132142022 is an abundant number, since it is smaller than the sum of its proper divisors (12640514362).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12132142022 is a wasteful number, since it uses less digits than its factorization.
12132142022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1162 (or 1083 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 12132142022 its reverse (22024123121), we get a palindrome (34156265143).
The spelling of 12132142022 in words is "twelve billion, one hundred thirty-two million, one hundred forty-two thousand, twenty-two".
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