Base | Representation |
---|---|
bin | 10110100110010011… |
… | …00101100101011101 |
3 | 1011022112022211102221 |
4 | 23103021211211131 |
5 | 144321401043123 |
6 | 5323520145341 |
7 | 606440020252 |
oct | 132311454535 |
9 | 34275284387 |
10 | 12132440413 |
11 | 51664a0065 |
12 | 2427168251 |
13 | 11b4726032 |
14 | 831455429 |
15 | 4b01d225d |
hex | 2d326595d |
12132440413 has 2 divisors, whose sum is σ = 12132440414. Its totient is φ = 12132440412.
The previous prime is 12132440401. The next prime is 12132440417. The reversal of 12132440413 is 31404423121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10523066724 + 1609373689 = 102582^2 + 40117^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12132440413 is a prime.
It is a super-2 number, since 2×121324404132 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12132440417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066220206 + 6066220207.
It is an arithmetic number, because the mean of its divisors is an integer number (6066220207).
Almost surely, 212132440413 is an apocalyptic number.
It is an amenable number.
12132440413 is a deficient number, since it is larger than the sum of its proper divisors (1).
12132440413 is an equidigital number, since it uses as much as digits as its factorization.
12132440413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12132440413 its reverse (31404423121), we get a palindrome (43536863534).
The spelling of 12132440413 in words is "twelve billion, one hundred thirty-two million, four hundred forty thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •