Base | Representation |
---|---|
bin | 1011000010001111011011… |
… | …1110000111010101100111 |
3 | 1120221220201202202211100121 |
4 | 2300203312332013111213 |
5 | 3042242123031401043 |
6 | 41445514500022411 |
7 | 2361406204615342 |
oct | 260436676072547 |
9 | 46856652684317 |
10 | 12133131122023 |
11 | 39586a523228a |
12 | 143b595091a07 |
13 | 6a01c3198032 |
14 | 2dd364c63459 |
15 | 160925ac8ded |
hex | b08f6f87567 |
12133131122023 has 2 divisors, whose sum is σ = 12133131122024. Its totient is φ = 12133131122022.
The previous prime is 12133131122003. The next prime is 12133131122033. The reversal of 12133131122023 is 32022113133121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12133131122023 is a prime.
It is a super-2 number, since 2×121331311220232 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12133131122003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066565561011 + 6066565561012.
It is an arithmetic number, because the mean of its divisors is an integer number (6066565561012).
Almost surely, 212133131122023 is an apocalyptic number.
12133131122023 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133131122023 is an equidigital number, since it uses as much as digits as its factorization.
12133131122023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 12133131122023 its reverse (32022113133121), we get a palindrome (44155244255144).
The spelling of 12133131122023 in words is "twelve trillion, one hundred thirty-three billion, one hundred thirty-one million, one hundred twenty-two thousand, twenty-three".
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